Simultaneous Linear Equations (2 Variables)#
Linear Equations Revision#
Theory#
Before solving systems of linear equations, let’s review single linear equations. A linear equation in one variable has the form:
where \(a \neq 0\). The solution is \(x = -\frac{b}{a}\).
For two variables, a linear equation takes the form:
This represents a straight line in the coordinate plane. A single linear equation in two variables has infinitely many solutions - all the points on the line.
Application#
Examples#
Example 1#
Find three solutions to: \(2x + 3y = 12\)
Solution:
\(2x + 3y = 12 \quad \text{(Choose values for x and solve for y)}\)
When \(x = 0\): \(3y = 12\), so \(y = 4 \quad \text{(Solution: (0, 4))}\)
When \(x = 3\): \(6 + 3y = 12\), so \(y = 2 \quad \text{(Solution: (3, 2))}\)
When \(x = 6\): \(12 + 3y = 12\), so \(y = 0 \quad \text{(Solution: (6, 0))}\)
Interactive Visualization: Linear Equations in Two Variables#
Multiple Choice Questions#
Simultaneous Linear Equations (2 Variables)#
Theory#
A system of simultaneous linear equations consists of two or more linear equations that must be satisfied at the same time. For two equations in two variables:
The solution is the point \((x, y)\) where both lines intersect. There are three possible outcomes:
Unique Solution: Lines intersect at exactly one point
No Solution: Lines are parallel (inconsistent system)
Infinitely Many Solutions: Lines are identical (dependent system)
The main methods for solving simultaneous linear equations are:
Graphical Method: Plot both lines and find their intersection
Substitution Method: Solve one equation for a variable and substitute
Elimination Method: Add or subtract equations to eliminate a variable
Matrix Method: Use matrices and row operations
Tip
Always check your solution by substituting the values back into both original equations. This verifies correctness and catches arithmetic errors.
Interactive Visualization: Simultaneous Linear Equations#
Application#
Examples#
Example 1#
Solve by substitution: \(\begin{cases} x + 2y = 7 \\ 3x - y = 4 \end{cases}\)
Method 1: Substitution
\(x + 2y = 7 \quad \text{(Solve for x in terms of y)}\)
\(x = 7 - 2y \quad \text{(Substitute into second equation)}\)
\(3(7 - 2y) - y = 4 \quad \text{(Expand and simplify)}\)
\(21 - 6y - y = 4 \quad \text{(Combine like terms)}\)
\(21 - 7y = 4 \quad \text{(Solve for y)}\)
\(-7y = -17\), so \(y = \frac{17}{7} \quad \text{(Find x)}\)
\(x = 7 - 2(\frac{17}{7}) = 7 - \frac{34}{7} = \frac{15}{7} \quad \text{(Solution: \)(\frac{15}{7}, \frac{17}{7})\()}\)
Example 2#
Solve by elimination: \(\begin{cases} 2x + 3y = 11 \\ 5x - 2y = 4 \end{cases}\)
Method 1: Elimination
\(\begin{cases} 2x + 3y = 11 \\ 5x - 2y = 4 \end{cases} \quad \text{(Multiply first by 2, second by 3)}\)
\(\begin{cases} 4x + 6y = 22 \\ 15x - 6y = 12 \end{cases} \quad \text{(Add equations to eliminate y)}\)
\(19x = 34 \quad \text{(Solve for x)}\)
\(x = \frac{34}{19} = \frac{34}{19} \quad \text{(Substitute back)}\)
\(2(\frac{34}{19}) + 3y = 11 \quad \text{(Solve for y)}\)
\(\frac{68}{19} + 3y = 11\), so \(3y = \frac{209 - 68}{19} = \frac{141}{19}\)
\(y = \frac{47}{19} \quad \text{(Solution: \)(\frac{34}{19}, \frac{47}{19})\()}\)
Example 3#
Identify the nature of the system: \(\begin{cases} 2x + 4y = 6 \\ x + 2y = 3 \end{cases}\)
Method 1: Analysis
\(2x + 4y = 6 \quad \text{(Divide by 2)}\)
\(x + 2y = 3 \quad \text{(Compare with second equation)}\)
\(x + 2y = 3 \quad \text{(Both equations are identical)}\)
Therefore, the system has infinitely many solutions. All points on the line \(x + 2y = 3\) are solutions.
Multiple Choice Questions#
Sector Specific Questions: Simultaneous Linear Equations Applications#
Key Takeaways#
Important
A system of two linear equations in two variables can have one solution, no solution, or infinitely many solutions
Graphically, the solution is where the two lines intersect
Substitution method: solve one equation for a variable and substitute into the other
Elimination method: add or subtract equations to eliminate a variable
For unique solution: lines intersect at one point (different slopes)
For no solution: lines are parallel (same slope, different y-intercepts)
For infinitely many solutions: lines are identical (same slope and y-intercept)
Always verify solutions by substituting back into both original equations